Kirchhoff"s Law


Before we discuss this topic we must first understand some basic concepts of network topology.
in a circuit there is what we called the BRANCHES, NODES and LOOPS.


branch- represents a single element such as a voltage source or a resistor. (boxed)
node- is the point of connection between two or more branches. (circled)
loop-is any closed path in a current. (directional arrow)

In our circuit, we have 4 branches, namely the voltage source current source and two resistors, three nodes indicated by a dot in a circuit, and two loops. If you wonder why there are only three nodes, it is because the two nodes constitute a single node.

a network with branches (b), nodes (n), and loops (l) will satisfy the fundamental theorem of network topology.
Now, let's name the branches that we will use for this whole discussion.



Independent voltage source                                                      dependent voltage source
                                                                         

   
Independent current source                                                         dependent current source

resistors

                                  
             
                                          
Kirchhoff's Current Law or KCL


                                                   
                                                    current entering    =     current leaving


KCL states that the algebraic sum of the currents in all the branches that converge in a common node is equal to zero.


I= I2 + I3

I+ I4  = I2 + I+ I5



Kirchhoff's Voltage Law or KVL


KVL

states that the algebraic sum of the voltages between successive nodes in a closed path in a circuit is equal to zero. We assume that the Resistor has its polarity and our loop is in clockwise direction.




we will use V = I x R in every resistor cause KVL talks about voltage. every loop has one equation so in this circuit we have 1 equations. For resistors we have unknown polarities so lets assume that all current from the resistors are positive.

equation:     Rx I+ RI1 + V = O , 

is positive because in my convention I get the first sign as where the directional arrow enters first so that my equation contains less negative signs.
           
you may use also this equation;  -(Rx I) -(RI1) - V = O as long as your current from all resistors are set to negative and V must read the last sign but for the whole discussion we will use the first equation's convention.



1st eq.   Rx I+ Rx (I1-I2) + V = O

(I1-I2came from resistor 2 because the two current shares one resistor at a time.

2nd eq.   R3 x I2 + R2 x (I2- I1) - V = O

(I2 - I1) still came from resistor 2 previously I1 comes first because we are in loop 1 but this time I2 comes first because we are in loop 2. 

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